Heredity and Variation: MCQs Quiz – 4 14


It's only fair to share...Share on Facebook
Facebook
Tweet about this on Twitter
Twitter
Email this to someone
email
Pin on Pinterest
Pinterest
Share on Tumblr
Tumblr

‘Heredity and Variation’/’Principles of Inheritance and Variation’ Questions:  Solve online MCQs (Multiple Choice Questions) with answers and test reporting. Test No. 4

Heredity and Variation: MCQs Quiz - 4

Congratulations - you have completed Heredity and Variation: MCQs Quiz - 4. You scored %%SCORE%% out of %%TOTAL%%. Your performance has been rated as %%RATING%%
Your answers are highlighted below.
Question 1
If two pea plants having red (dominant) coloured flowers with unknown genotypes are crossed, 75% of the flowers are red and 25% are white. The genotypic constitution of the parents having red coloured flowers will be
A
Both heterozygous
B
One homozygous and other heterozygous
C
Both homozygous
D
Both hemizygous
Question 2
In a given plant, red colour (R) of fruits is dominant over white fruit (r); and tallness (T) is dominant over dwarfness (t). If a plant with genotype RrTt is crossed with a plant of genotype rrtt, what will be the percentage of tall plants with red fruits in the next generation?
A
20%
B
40%
C
50%
D
60%
Question 3
In Drosophila, the sex is determined by:
A
The ratio of pairs of X-chromosomes to the pairs of autosomes
B
X and Y chromosomes
C
The ratio of number of X-chromosomes to the sets of autosomes
D
Whether the egg is fertilized or develops parthenogenetically
Question 4
In Mendel's experiments with garden pea, round seed shape (RR) was dominant over wrinkled seeds (rr), yellow cotyledon (YY) was dominant over green cotyledon (yy). What are the expected phenotypes in the F2 generation of the cross RRYY × rryy?
A
Only wrinkled seeds with green cotyledons
B
Only wrinkled seeds with yellow cotyledons
C
Only round seeds with green cotyledons
D
Round seeds with yellow cotyledons, and wrinkled seeds with yellow cotyledons
Question 5
In pea plants, yellow seeds are dominant to green. If a heterozygous yellow seeded plant is crossed with a green seeded plant, what ratio of yellow and green seeded plants would you expect in F1 generation?
A
3 : 1
B
50 : 50
C
9 : 1
D
1 : 3
Question 6
Mating  of  an  organism   to  a  double  recessive  in  order  to  determine  whether  it  is homozygous or heterozygous for a character under consideration is called
A
reciprocal cross
B
test cross
C
dihybrid cross
D
back cross
Question 7
When a tall plant with round seeds (TTRR) crossed with a dwarf plant with wrinkle seeds (tfrr). The F1 generation consists of tall plants with round seeds. What would be the proportion of dwarf plant with wrinkle seeds in F1 generation?
A
0
B
1/2
C
1/4
D
1/16
Question 8
Phenotype of an organism is the result of
A
Environmental changes and sexual dimorphism
B
Cytoplasmic effects and nutrition
C
Mutations and linkages
D
Genotype and environment interactions
Question 9
Sickle cell anemia is
A
Characterized by elongated sickle like RBCs with a nucleus
B
An autosomal linked dominant trait
C
Caused by substitution of valine by glutamic acid in the β globin chain of haemoglobin
D
Caused by a change in a single base pair of DNA
Question 10
Which one of the following conditions correctly describes the manner of determining the sex in the given example?
A
Homozygous sex chromosomes (XX) produce male in Drosophila
B
Homozygous sex chromosomes (ZZ) determine female sex in birds
C
XO type of sex chromosomes determine male sex in grasshopper
D
XO condition in humans as found in Turner Syndrome, determines female sex
Question 11
Test cross of dihybrid ratio 1 : 1 : 1 : 1 then it proves that
A
F1 hybrid produces four different progenies
B
F1 hybrid produces two different progenies
C
F1 hybrid is homozygous
D
Four different progenies are produced by parents
Question 12
The F2 generation offspring in a plant showing incomplete dominance, exhibit
A
variable genotypic and phenotypic ratios
B
a genotypic ratio of 1 : 1
C
a phenotypic ratio of 3 : 1
D
similar phenotypic and genotypic ratios of 1 : 2 : 1
Question 13
Two genes R and Y are located very close on the chromosomal linkage map of maize plant. When RRYY and rryy genotypes are hybridized, the F2 segregation will show:
A
Higher number of the parental types
B
Higher number of the recombinant types
C
Segregation in the expected 9 : 3 : 3 : 1 ratio
D
Segregation in 3 : 1 ratio
Question 14
Two pea plants were subjected cross pollination. Of the 183 plants produced in the next generation, 94 plants were found to be tall and 89 plants were found to be dwarf. The genotypes of the two parental plants are likely to be
A
TT and tt
B
Tt and Tt
C
Tt and tt
D
TT and TT
Question 15
Which of the following pair of features is a good example of polygenic inheritance?
A
Hair pigment of mouse and tongue rolling in humans
B
ABO blood group in humans and flower colour of Mirabilis jalapa
C
Human height and skin colour
D
Human eye colour and sickle cell anaemia
Once you are finished, click the button below. Any items you have not completed will be marked incorrect. Get Results
There are 15 questions to complete.

Post your comments and grade this MCQs test at the end of the post.


Leave a comment

Your email address will not be published. Required fields are marked *

14 thoughts on “Heredity and Variation: MCQs Quiz – 4

  • laxmi gupta

    in question 2 how it is 50%? plz give explanation

  • mannat

    subsitutuion of GLUTAMIC ACID by VALINE is correct..
    not viceversa..
    in quest 9 .

  • Anirban ghosh

    excellent!!!!!! i like these questions i hope that these all are going to come in the exam

  • Srimoyee Gupta

    in question 14 what type of ratio has been obeyed? is it a case of incomplete domiance?

  • Krishnakant Jha

    Please make a correction in Q2, It has To be RrTt, instead of RRTt. That is if both is heterozygous then only the ratio is 50%.

      • simran

        sorry sir….but in Q 2 the genotype of plant should be RRTt….then only the ratio is 50% ….otherwise the no. of taal plants with red flowers is only 4 out of 16….so it cannot be 50%….it should be RRTt

  • shimpy priya

    in 9th que (d)is the correct ans and not (c),sickle cell anaemia is caused by the substitution of glutamic acid by valine but it is given opposite.consult NCERT

    • delightdev

      absolutely !!!
      similarly there are few snag, but the problem is that after the user highlights it, they don’t do the needful!!!

      • Administrator Post author

        Dear Dev/Priya, while I wholeheartedly appreciate your enthusiasm and participation on our blog and forum, simultaneously we need to verify the authenticity of student’s response as well. Consequently it might have delayed the response from publisher’s end. More importantly it is a free service ………., isn’t it? Dev thanking you honestly for your focus and replies.

  • Nisha Tripathi

    In que. 10 in first option there will be male instead of make